A triangular poster has a base of 2 1/2 feet and a height of 1 3/4 feet what is the area of the poster

Accepted Solution

Answer:a=[tex]2\frac{3}{16}[/tex]Step-by-step explanation:formulas:a= b x h x [tex]\frac{1}{2}[/tex]or           (both equations get the same answers)a= b x h ÷ 2imma stick with the second one kuz i usually use that one but ur preference.so,base(b) = [tex]2\frac{1}{2}[/tex] = [tex]\frac{5}{2}[/tex]height(h) = [tex]1\frac{3}{4}[/tex] = [tex]\frac{7}{4}[/tex]now fill it in to the equation:a=b x h x [tex]\frac{1}{2}[/tex]                        a= b x h ÷ 2a=[tex]\frac{5}{2}[/tex] x [tex]\frac{7}{4}[/tex] x [tex]\frac{1}{2}[/tex]                         a=[tex]\frac{5}{2}[/tex] x [tex]\frac{7}{4}[/tex] ÷ 2a=[tex]\frac{35}{16}[/tex]                                   a=[tex]\frac{35}{16}[/tex] ÷ 2a=[tex]2\frac{3}{16}[/tex]                                   a=[tex]\frac{35}{8}[/tex] ÷ 2                                           a=[tex]\frac{35}{16}[/tex]                                              a=[tex]2\frac{3}{16}[/tex]o well i did both lol now you ca compare the two equations now  :]plz give brainliesttttt